This week in Maths, Haylee, Florence and I worked together to solve a maths challenge. In our strategy, we used the most efficient one, we found more confident. We started off by adding up all of combos that are $7.00 with how many people need them. Then we multiplied the total by 7 equaling 441. After that, we added up the total of the chicken combo which cost $7.50. Then we multiplied the total by 7.50 which equals 390. Once we did that, we added the two totals, which equals to 831.
Wednesday, 17 June 2020
Subway Challenge
LI: To find the most efficient strategy to solve the problem.
This week in Maths, Haylee, Florence and I worked together to solve a maths challenge. In our strategy, we used the most efficient one, we found more confident. We started off by adding up all of combos that are $7.00 with how many people need them. Then we multiplied the total by 7 equaling 441. After that, we added up the total of the chicken combo which cost $7.50. Then we multiplied the total by 7.50 which equals 390. Once we did that, we added the two totals, which equals to 831.
This week in Maths, Haylee, Florence and I worked together to solve a maths challenge. In our strategy, we used the most efficient one, we found more confident. We started off by adding up all of combos that are $7.00 with how many people need them. Then we multiplied the total by 7 equaling 441. After that, we added up the total of the chicken combo which cost $7.50. Then we multiplied the total by 7.50 which equals 390. Once we did that, we added the two totals, which equals to 831.
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